Question

Помогите пж даю 80 баллов

Answer 1

$\dfrac{3a^2+3ab}{3a^2}=\dfrac{3a\, (a+b)}{3a^2}=\dfrac{a+b}{a}\\\\\\\dfrac{81x^2-y^2}{9x+y}=\dfrac{(9x-y)(9x+y)}{9x+y}=9x-y$

$\dfrac{25x^2+10x+1}{10x+2}=\dfrac{(5x+1)^2}{2\cdot (5x+1)}=\dfrac{5x+1}{2}\\\\\\\dfrac{a-2}{a^3-8}=\dfrac{a-2}{(a-2)(a^2+2a+4)}=\dfrac{1}{a^2+2a+4}$