Question

помогите пж 7 вопрос ,,,,,,​

Answer 1

Ответ:

$\frac{(x^3*x^6)^4}{x^{33}} = \frac{(x^9)^4}{x^{33}} = \frac{x^{36}}{x^33} = x^3\\\\(-\frac{2}{3} )^3 = (-\frac{2}{3} )*(-\frac{2}{3} )*(-\frac{2}{3} ) = -\frac{8}{27}$