Question

помогите пж 10;11;12 срочно помогитееен

Answer 1

$10) = frac{6c(b - 3c)}{ {(b - 3c)}^{2} } = frac{6c}{b - 3c}$
$11) = frac{(a + 5)(a + 5)}{(a + 5)(a - 5)} = frac{a + 5}{a - 5}$
$12) = frac{(a - b)( {a}^{2} + ab + {b}^{2}) }{a - b} = {a}^{2} + ab + {b}^{2}$