Question

Помогите пожайлуйста!!!​

Answer 1

$\frac{8-x^{2}}{x^{2}-8x}+\frac{x+8}{x-8}=\frac{4}{x}\\\\\frac{8-x^{2}}{x(x-8)}+\frac{x+8}{x-8}=\frac{4}{x}\\\\\frac{8-x^{2}+x^{2}+8x}{x(x-8)}-\frac{4}{x}=0\\\\\frac{8x+8}{x(x-8)}-\frac{4}{x}=0\\\\\frac{8x+8-4x+32}{x(x-8)}=0\\\\\frac{4x+40}{x(x-8)}=0\\\\\left \{ {{4x+40=0} \atop {x\neq0;x\neq 8}} \right.\\\\4x=-40\\\\x=-10\\\\Otvet:-10$