Question

Помогите, пожалуйста. Заранее спасибо!

Answer 1

Ответ:

Объяснение:

(4^2 -x^2)/(x-4)=(4-x)(4+x)/(x-4)= -(4+x)= -4-x

(3a-1-3b+1)/(a^2 -b^2)=3(a-b)/((a-b)(a+b))=3/(a+b)

(2a+b+2b-5a)/(a -b)^2=​3(b-a)​​/(a -b)^2= -3(a -b)/(a -b)^2= -3/(a -b)

(5^2 -a^2)/(a+5)=(5-a)(5+a)/(a+5)=5-a

(x-3+11)/(x^2 -8^2)=(x+8)/((x-8)(x+8))=1/(x-8)

(13x+6y-11x-4y)/(x+y)^2=2(x+y)/(x+y)^2=2/(x+y)

x/(y-1) -5/(y-1)=(x-5)/(y-1)

2m/(m-n) -2n/(m-n)=2(m-n)/(m-n)=2

(a^2 +4^2 -8a)/(a-4)=(a-4)^2/(a-4)=a-4

a/(с-3) +6/(c-3)=(a+6)/(c-3)

(5p-10q)/(2q-p)= -5(2q-p)/(2q-p)= -5

(x^2 +(3y)^2 -6xy)/(x-3y)=(x-3y)^2 /(x-3y)=x-3y

(10p-3p)/(p-q)=7p/(p-q)

(x-3+2)/(x-1)=(x-1)/(x-1)=1

(a-3)/(a^2 -3^2)=1/(a-3)

5(a-b)/(a-b)=5

(a-3a+b)/(2a-b)=(-2a+b)/(2a-b)= -(2a-b)/(2a-b)= -1

(y^2 -1)/(y-1)=(y-1)(y+1)/(y-1)=y+1