Question

Помогите, пожалуйста, упростить

Answer 1

$frac{(2x^{1/2})^3y^2z^{3/4}}{4x^2y^{1/2}z^{3/2}} = frac{8x^{3/2}y^{2-1/2}}{4x^2z^{3/2-3/4}}= frac{2y^{3/2}}{x^{2-3/2}z^{3/4}}} =\\= frac{2y^{3/2}}{x^{1/2}z^{3/4}}= frac{2y^{1,5}}{x^{0,5}z^{0,75}}$