Question

Помогите пожалуйста, срочно!

Answer 1

$log^2frac{pi}{6}=a; to ; logfrac{pi}{6}=pm sqrt{a}\\frac{log_2(arccos(-frac{1}{2}))-3}{log_2pi -log_23-1}=frac{log_2(pi -frac{pi}{3})-log_28}{log_2frac{pi}{3}-log_22}=frac{log_2frac{2pi }{3cdot 8}}{log_2frac{pi}{3cdot 2}}=frac{log_2frac{pi}{12}}{log_2frac{pi}{6}}=\\=frac{log_2(frac{1}{2}cdot frac{pi}{6})}{log_2frac{pi}{6}}=frac{log_2frac{1}{2}+log_2frac{pi}{6}}{log_2frac{pi}{6}}=frac{-1+log_2frac{pi}{6}}{log_2frac{pi}{6}}=$

$= left { {{frac{-1+sqrt{a}}{sqrt{a}}} atop {frac{-1-sqrt{a}}{-sqrt{a}}=frac{1+sqrt{a}}{sqrt{a}}} right.$