Question

помогите пожалуйста!! срочно​

Answer 1

$\frac{1 - b {}^{2} }{ 3ab} + \frac{2b {}^{3} - 1 }{6ab {}^{2} } = \frac{2b \times (1 - b {}^{2} ) + 2b {}^{3} - 1}{6ab {}^{2} } = \frac{2b - 2b {}^{3} + 2b {}^{3} - 1}{6ab {}^{2} } = \frac{2b - 1}{6ab {}^{2} }$