Question

Помогите пожалуйста:)
Решите систему уравнений!!!

(х-3)^2 +(у-3)^2=4
х-у=-2

Answer 1

$left { {{(x-3)^2+(y-3)^2=4} atop {x-y=-2}} right. ; left { {{(x-3)^2+(x+2-3)^2=4} atop {y=x+2}} right. ; left { {{2x^2-8x+6=0} atop {y=x+2}} right. ; left { {{x^2-4x+3=0} atop {y=x+2}} right. \\ left { {{x_1=1,x_2=3} atop {y_1=3,y_2=5}} right. ; ; Otvet:; (1,3),; (3,5).$