Question

Помогите пожалуйста решить!!! ​

Answer 1

1) Способ подстановки :

$\left \{ {{2x-3y=3} \atop {x-y=2}} \right. \\\\\left \{ {{2(2+y)-3y=3} \atop {x=2+y}} \right. \\\\\left \{ {{4+2y-3y=3} \atop {x=2+y}} \right. \\\\\left \{ {{-y=-1} \atop {x=2+y}} \right. \\\\\left \{ {{y=1} \atop {x=2+1}} \right.\\\\\left \{ {{y=1} \atop {x=3}} \right. \\\\Otvet:\boxed{(3 \ ; \ 1)}$

2) Способ сложения :

$\left \{ {{2x-3y=3} \atop {x-y=2}|*(-3)} \right. \\\\+\left \{ {{2x-3y=3} \atop {-3x+3y=-6}} \right. \\-------\\-x=-3\\\\x=3\\\\y=x-2=3-2=1\\\\Otvet:\boxed{(3 \ ; \ 1)}$