Question

Помогите пожалуйста решить 265 полностью!

Answer 1

$3sqrt{20}-sqrt{5}=3sqrt{5}sqrt{2^2}-sqrt{5}=3cdot 2sqrt{5}-sqrt{5}=6sqrt{5}-sqrt{5}=5sqrt{5}$

$frac{1}{3}sqrt{18}+2sqrt{2}= frac{1}{3} cdot 3sqrt{2}+2sqrt{2}= sqrt{2}+2sqrt{2}=3sqrt{2}$

$2sqrt{27}-sqrt{12}=6sqrt{3}-2sqrt{3}=4sqrt{3}$

$2sqrt{20}-2sqrt{45}+frac{1}{4}sqrt{16} = 4sqrt{5}-6sqrt{5}+1= 1-2sqrt{5}$

$5sqrt{8}+frac{1}{2}sqrt{2}-2sqrt{18}=10sqrt{2}+frac{1}{2}sqrt{2}-6sqrt{2}=4frac{1}{2}cdot sqrt{2}$

$3sqrt{48}-sqrt{75}+frac{1}{7}sqrt{147} =12sqrt{3}-5sqrt{3}+sqrt{3} = 8sqrt{3}$

Answer 2

Большое спасибо вам