Question

Помогите пожалуйста решить!!

Answer 1

1) Одз: x>3
Log4(x-3)<=2
Log4(x-3)<=log4(16)
x-3<=16
x<=19
2) (1/4)^x-3<=1/16
(1/4)^x-3<=(1/4)^2
x-3<=2
x<=5
3) 0,3^x+2<=0,09
0,3^x+2<=0,3^2
x+2<=2
x<=0