Question

ПОМОГИТЕ ПОЖАЛУЙСТА.. ПОЖАААЛУЙСТААА(((​

Answer 1

$\displaystyle\bf\\\left \{ {{\dfrac{x-4}{2} +\dfrac{y+11}{4} =1} \atop {\dfrac{x+7}{3} +\dfrac{y-4}{7} =2}} \right. \\\\\\\left \{ {{\dfrac{x-4}{2} \cdot 4+\dfrac{y+11}{4} \cdot 4=1\cdot 4} \atop {\dfrac{x+7}{3} \cdot 21+\dfrac{y-4}{7} \cdot 21=2\cdot 21}} \right. \\\\\\\left \{ {{(x-4)\cdot 2+(y+11)=4} \atop {(x+7)\cdot 7+(y-4)\cdot 3=42}} \right. \\\\\\\left \{ {{2x-8+y+11=4} \atop {7x+49+3y-12=42}} \right. \\\\\\\left \{ {{2x+y=1} \ |\cdot(-3)\atop{7x+3y=5}} \right.$

$\displaystyle\bf\\+\left \{ {{-6x-3y=-3} \atop {7x+3y=5}} \right. \\----------\\x=2\\\\y=1-2x=1-2\cdot 2=1-4=-3\\\\Otvet: \ (2 \ ; \ -3)$