Question

Помогите пожалуйста 8 класс ср

Answer 1

Ответ:

Надеюсь поймёте...........

Answer 2

Объяснение:

1.

$a) \: 5 {}^{ - 2} = (\frac{1}{5} ) {}^{2} = \frac{1}{25} = \frac{4}{100} = 0.04$

$b) \: 12 \times 3 {}^{ - 3} = 12 \times (\frac{1}{3} ) {}^{3} = 4 \times ( \frac{1}{3}) {}^{2} = 4 \times \frac{1}{9} = \frac{4}{9}$

$в) \: (27 \times 3 {}^{ - 2} ) {}^{ - 1} = \frac{1}{ 27 \times 3 {}^{ - 2} } = \frac{1}{ 27 \times {( \frac{1}{3}) }^{ 2} }=\frac{1}{ 27 \times \frac{1}{9} } = \frac{1}{3}$

$г) \: \frac{ {2}^{ - 3} \times2 {}^{2} }{2 {}^{ - 4} } = \frac{2 {}^{ - 3 + 2} }{2 {}^{ - 4} } = \frac{2 {}^{-1} }{2 {}^{-4} } = 2 {}^{ - 1-(-4)} = 2 {}^{3} = 8$

2.

$a) \: x {}^{ - 3} \times x {}^{5} \div x {}^{ - 6} = x {}^{ - 3 + 5 - ( - 6)} = x {}^{ - 3 + 11} = x {}^{8}$

$b) \: 12y{}^{-7} \div ( \frac{3}{4} {y}^{-5})= \frac{12}{y{}^{7}} \div (\frac{3}{4{y}^5})=\frac{12}{y{}^{7}} \times (\frac{4{y}^5}{3}) = \frac{4 \times 4{y}^{5}}{{y}^{7}}= \frac{16}{{y}^{2}}$