Question

Помогите пожалуйста!!!!!!!!!!!!!!!!!!!

Answer 1

${x}^{1 + lgx } = 100 \\ lg {x}^{1 + lgx } = lg100 \\ (1 + lgx)lgx = 2 \\ lg^{2}x + lgx - 2 = 0 \\ lgx = t \\ {t}^{2} + t - 2 = 0 \\ t_{1}= 1 \\ t_{2}= - 2 \\ lgx = 1 \\ x = 10 \\ lgx = - 2 \\ x = {10}^{ - 2} = \frac{1}{100} = 0.01$