Question

помогите пожалуйста

Answer 1

$\displaystyle\bf\\1)\\\\\frac{x-3}{4} =2\\\\x-3=4\cdot 2\\\\\boxed{x-3=8}\\\\\\2)\\\\\frac{2x-10}{x} =0\\\\\left \{ {{2x-10=0} \atop {x\neq 0}} \right. \ \ \ \Rightarrow \ \ \ \left \{ {{x=5} \atop {x\neq 0}} \right. \\\\Otvet \ : \ B\\\\\\3)\\\\(x-1)(x+2)=0\\\\\\\left[\begin{array}{ccc}x-1=0\\x+2=0\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{1} =1\\x_{2} =-2\end{array}\right$

Otvet : Б