Question

Помогите пожалуйста ......​

Answer 1

Ответ:

$f'(x) = \frac{(3 {x}^{2} - 1)'(x - 3) - (x - 3)'(3 {x}^{2} - 1) }{ {(x - 3)}^{2} } = \\ = \frac{6x(x - 3) - 1 \times (3 {x}^{2} - 1) }{ {(x - 3)}^{2} } = \\ = \frac{6 {x}^{2} - 18x - 3 {x}^{2} + 1}{ {(x - 3)}^{2} } = \frac{3 {x}^{2} - 18x + 1 }{ {(x - 3)}^{2} }$