Question

помогите пожалуйста ​

Answer 1

Ответ:

а

$f'(x) = 3 \times 2x + 4 = 6x + 4$

$f'( - 1) = - 6 + 4 = - 2$

б

$f'(x) = - 1.5 \sin(x) \\ f'(\frac{\pi}{6}) = - 1.5 \sin( \frac{\pi}{6} ) = - \frac{3}{2} \times \frac{1}{2} = - 0.75$

в

$f'(x) = \frac{( \cos(x)) \times (1 - x) - (1 - x) \times \cos(x) }{ {(1 - x)}^{2} } = \\ = \frac{ - \sin(x)(1 - x) + \cos(x) }{ {(1 - x)}^{2} } = \\ = \frac{(x - 1) \sin(x) + \cos(x) }{ {(1 - x)}^{2} }$

$f'(0) = \frac{ - 1 \sin(0) + \cos(0) }{(1 - 0) {}^{2} } = \frac{1}{1} = 1$