Question

помогите пожалуйста ​

Answer 1

Ответ:

$( \frac{2}{3} + x) {}^{2} = ( \frac{4}{9} + \frac{4}{3} + x {}^{2} )$

$(5y - \frac{3}{4} ) {}^{2} = (25y {}^{2} - \frac{15}{2} + \frac{9}{16} )$

$( \frac{1}{2} b + c) {}^{2} = ( \frac{1}{4} b {}^{2} + bc + c {}^{2} )$

$(10a {}^{2} + 9c) {}^{2} = (100a {}^{4} + 180 {a}^{2} c + 81 {c}^{2} )$

$102 {}^{2} = (100 + 2) {}^{2} = (10000 + 400 + 4) = 10404$

$104 {}^{2} = (100 + 4) {}^{2} = (10000 + 800 + 16) = 10816$

$98 {}^{2} = (100 - 2) {}^{2} = (10000 - 400 + 4) = 9604$