Question

Помогите пожалуйста

Answer 1

Ответ:

$1)y' = 2x - 3$

$2)y' = ( \frac{2x}{ \sqrt{x} } + \frac{1}{ \sqrt{x} } )' = (2 {x}^{ \frac{1}{2} } + {x}^{ - \frac{1}{2} } )' = {x}^{ - \frac{1}{2} } - \frac{1}{2} {x}^{ - \frac{3}{2} } = \frac{1}{ \sqrt{x} } - \frac{1}{2x \sqrt{x} }$

$3)y' = \frac{ \frac{1}{ { \cos(x) }^{2} } \times (1 + {x}^{2} ) + 2x \tan(x) }{ {(1 + {x}^{2}) }^{2} }$

$4)y' = ln(6) \times {6}^{x} \times \cos(x) - \sin(x) \times {6}^{x}$

$5)y' = - 3 \sin(x)$

$6)y' = \frac{1}{ ln(6) \times x} \times \sqrt{x} + \frac{1}{2} {x}^{ \frac{ - 1}{2} } log_{6}(x) = \frac{ \sqrt{x} }{x ln(6) } + \frac{ log_{6}(x) }{2 \sqrt{x} }$

$7)y' = \frac{2 \cot(x) - ( - \frac{1}{ { \sin(x) }^{2} })2x }{ { \cot(x) }^{2} } = \frac{2}{ \cot(x) } + \frac{2x}{ { \sin(x) }^{2} \times { \cot(x) }^{2} }$