Question

ПОМОГИТЕ ПОЖАЛУЙСТА!!

Answer 1

$\dfrac{12p^2-q}{4p}-3p=\dfrac{12p^2-q}{4p}-\dfrac{12p^2}{4p}=\dfrac{12p^2-q-12p^2}{4p}=-\dfrac{q}{4p}=-\dfrac{28}{4\cdot(-0.35)}=\dfrac{28}{7\cdot4\cdot0.05}=\dfrac1{0.05}=\dfrac{~~1~~}{\dfrac1{20}}=\fbox{20}$