Question

помогите пожалуйста ​

Answer 1

Ответ:

1) $\sqrt{64} \sqrt{100} \sqrt{0,16} = 8*10\sqrt{\frac{4}{25} } = 8*10*\frac{2}{5} = 8*2*2=32$

2) $2\sqrt{0,81} + \sqrt{0,04} =2\sqrt{\frac{81}{100} } + \sqrt{\frac{1}{25} } = 2*\frac{9}{10}+\frac{1}{5} = \frac{9}{5} + \frac{1}{5} = 2$

3) $3\sqrt{25}- \frac{1}{3} * \sqrt{81} =3*5-\frac{1}{3} *9=15-3=12$

4) $\frac{1}{4} * \sqrt{\frac{16}{25} } + 7\sqrt{0,09} = \frac{1}{4} * \frac{4}{5} + 7\sqrt{\frac{9}{100} } = \frac{1}{5} + 7*\frac{3}{10} = \frac{1}{5}+ \frac{21}{10} = \frac{23}{10} = 2\frac{3}{10}$

5) $6\sqrt{1\frac{33}{36} } -7\sqrt{2\frac{2}{49} } =6\sqrt{\frac{49}{36} }-7\sqrt{\frac{100}{49} } = 6*\frac{7}{6} -7*\frac{10}{7} = 7-10=-3$

6) $\frac{1}{5} * \sqrt{1\frac{9}{16} } -\frac{2}{3} * \sqrt{1\frac{17}{64} } = \frac{1}{5} * \sqrt{\frac{25}{16} } -\frac{2}{3} * \sqrt{\frac{81}{64} } =\frac{1}{5} *\frac{5}{4} -\frac{2}{3} *\frac{9}{8} = \frac{1}{4} - \frac{3}{4} = -\frac{1}{2} = -0,5$

7) $\sqrt{\frac{16}{25} } \sqrt{\frac{225}{64} } =\frac{4}{5} * \frac{15}{8} = \frac{3}{2} =1\frac{1}{2} =1,5$