Question

помогите пожалуйста.​

Answer 1

$displaystyle 1)quad (sqrt{3})^3=sqrt{3^3}=sqrt{27}quadboxed{times}\\2)quad frac{sqrt{14}}{sqrt7}=sqrt{frac{14}7}=sqrt{2}quad boxed{times}\\3)quad(sqrt7+1)(sqrt7+1)=(sqrt7)^2+2sqrt7+1=7+2sqrt7+1=8+2sqrt7quad boxed{times}\\4)quad -(sqrt7+1)(1-sqrt7)=(sqrt7+1)(sqrt7-1)=(sqrt7)^2-1^2=7-1=6quad boxed{checkmark}$