Question

помогите пожалуйста!!!!!!!!!!!!!!!!!!!!

Answer 1

1)
$(2x - 1)(2x + 1) = x(2x + 3)$
$4 {x}^{2} - 1 - x(2x + 3) = 0$
$4 {x}^{2} - 1 - 2 {x}^{2} - 3x = 0$
$2 {x}^{2} - 3x - 1 = 0$
2)
${(3x + 2)}^{2} = (x + 2)(x - 3)$
$3 {x}^{2} + 12x + 4 - {x}^{2} + 3x - 2x \ + 6 = 0$
$2 {x}^{2} + 13x + 10 = 0$
3)
$(x + 1)(x + 2) = (2x - 1)(x - 2)$
${x}^{2} + 2x + x + 2 - \ 2 {x}^{2} + 4x + x - 2 = 0$
$- {x}^{2} + 8x + 0 = 0$
${x}^{2} - 8x = 0$
4)
$4 {x}^{2} - 2x(3x + 1) = 5$
$4 {x}^{2} - 6 {x}^{2} - 2x - 5 = 0$
$- 2 {x}^{2} - 2x - 5 = 0$
$2 {x}^{2} + 2x + 5 = 0$
5)
$(x + 3)(3x - 2) = (4x + 5) times \ (2x - 3)$
$3 {x}^{2} - 2x + 9x - \ 6 - 8 {x}^{2} + 12x - 10x + 15 = 0$
$- 5 {x}^{2} - 9x + 9 = 0$
$5 {x}^{2} + 9x - 9 = 0$
6)
${x}^{2} + (1 - x)(1 - 3x) = x$
${x}^{2} + 1 - 3x - x + 3 {x}^{2} - x = 0$
$4 {x}^{2} - 5x + 1 = 0$

Answer 2

Destroy