Question

Помогите пожалуйста

Answer 1

1)
$= log_{8}( frac{12}{15} times 20 ) = log_{8}( frac{4}{5} times 20) = log_{8}(16) = log_{ {2}^{3} }( {2}^{4} ) = frac{4}{3} times log_{2}(2) = frac{4}{3} times 1 = frac{4}{3}$
2)
${6}^{3x - 1} = {6}^{1 - 2x} \ 3x - 1 = 1 - 2x \ 3x + 2x = 1 + 1 \ 5x = 2 \ x = frac{2}{5}$

Answer 2

Спасибо большое

Answer 3

$log_{8} 12-log_{8}15+log_{8}20=log_{8}frac{12*20}{15} =log8_{16}=log_{2^{3}}2^{4}=frac{4}{3} log_{2} 2 =1frac{1}{3} \\\6^{3x-1} =6^{1-2x}\\3x-1=1-2x\\3x+2x=1+1\\5x=2\\x=0,4$