Question

ПОМОГИТЕ ПОЖАЛУЙСТА 1058

Answer 1

$1)\ (x+1)(x+2)-(x-3)(x+4)=6 \ x^2+2x+x+2-(x^2+4x-3x-12)=6 \ x^2+2x+x+2-x^2-x+12=6 \ 2x+14=6 \ 2x=-8 \ x=-4 \ 3) \ 24-(3y+1)(4y-5)=(11-6y)(2y-7) \ 24-12y^2+11y+5=22y-77-12y^2+42y \ 24+11y^2+5=22y-77+42y \ 29+11y=64y-77 \ 11y-64y=-77-29 \ -53y=-106 \ y=frac {-106}{-53} \ y=2$
$4) \ (6y+2)(5-y)=47-(2y-3)(3y-1) \ 30y-6y^2+10-2y=47-6y^2+11y-3 \ 30y+10-2y=47+11y-3 \ 28y-11y=44-10 \ 17y=34 \ y=frac {34}{17} \ y=2$