Question

Помогите пожалуйста, 10 класс
Задание 2 и 3

Answer 1

Ответ:

$2) {7}^{x - 2} = \frac{1}{ {3}^{x - 2} } \\ {7}^{x - 2} \times {3}^{x - 2} = 1 \\ {21}^{x - 2} = {21}^{0} \\ x - 2 = 0 \\ x = 2$

$3) {3}^{x + 4} - {3}^{x + 3} = - 3 \times {5}^{x + 3} + {5}^{x + 4} \\ {3}^{x + 3} (3 - 1) = {5}^{x + 3} ( - 3 + 5) \\ {3}^{x + 3} \times 2 = {5}^{x + 3} \times 2 \\ {3}^{x + 3} = {5}^{x + 3} \\ \frac{ {3}^{x + 3} }{ {5}^{x + 3} } = {( \frac{3}{5}) }^{0} \\ x + 3 = 0 \\ x = - 3$