Question

Помогите пож.
$\left \{ {{ \sqrt{x} - \sqrt{y} =1 } \atop { \sqrt{x} + \sqrt{y} = 19}} \right.$

Answer 1

$\left \{ {{\sqrt{x}-\sqrt{y}=1} \atop {\sqrt{x}+\sqrt{y}=19}} \right. \; ,\; \; \; t=\sqrt{x},\; p=\sqrt{y}\; \; \to \; \; \left \{ {{t-p=1} \atop {t+p=19}} \right. \; \to \\\\ \left \{ {{2t=20} \atop {2p=18}} \right. \; ,\; \left \{ {{t=10} \atop {p=9}} \right. \; ,\; \left \{ {{\sqrt{x}=10} \atop {\sqrt{y}=9}} \right. \; ,\; \left \{ {{x=100} \atop {y=81}} \right.$

Answer 2

$\left \{ {{ \sqrt{x} - \sqrt{y} =1 } \atop { \sqrt{x} + \sqrt{y} = 19}} \right.$

$[tex] \left \{ {{\sqrt{x}-\sqrt{y}=1} \atop {\sqrt{x}+\sqrt{y}=19}} \right. \; ,\; \; \; t=\sqrt{x}\; p=\sqrt{y}\; \; \to \; \; \left \{ {{t-p=1} \atop {t+p=19}} \right. \;$

${2p=18}} \right. \; \;$

$\left { {{t=10} \atop {p=9}}$

$\right. \; \left \{ {{\sqrt{x}=10} \atop {\sqrt{y}=9}}$

$\right.   \left \{ {{x=100} \atop {y=81}} \right.$