Question

Помогите под а пожалуйста

Answer 1

(3m+1)/(3m^2-27n^2) • (3m+9n)/(2+6m)=(3m+1)/(3(m-3n)(m+3n))  • (3(m+3n)/(2(1+3m)) = 1/(m-3n)• 1/2 = 1/(2m-6n)