помогите плз
log2x+log4x+log16x>3.5
Ответы на вопрос
Ответил pikosteadygirl1
0
log x + 1/2 log x + 1/4 log x >3.5
2 2 2
log x + log x^1/2 + log x^1/4 >3.5
2 2 2
log (x*x^1/2 *x^1/4)>3.5
2
log x^(7/4)> Log 2^(3.5)
2 2
x^7/4>12.25
x> (12.25)^4/7
2 2 2
log x + log x^1/2 + log x^1/4 >3.5
2 2 2
log (x*x^1/2 *x^1/4)>3.5
2
log x^(7/4)> Log 2^(3.5)
2 2
x^7/4>12.25
x> (12.25)^4/7
Ответил m11m
0
x^(7/4)>2^(7/2)
(x^(1/2))^(7/2)>2^(7/2)
x^(1/2)>2
x>4
(x^(1/2))^(7/2)>2^(7/2)
x^(1/2)>2
x>4
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