Question

помогите плз. 1) y^2-16=0.
2) x^5-x^3=0

Answer 1

$1) : (y - 4)(y + 4) = 0 \ y1 = 4 \ y2 = - 4 \ \ 2) {x}^{3} ( {x}^{2} - 1) = 0 \ {x}^{3} = 0. : : x1 = 0 \ {x}^{2} - 1 = 0 \ (x - 1)(x + 1) = 0 \ x2 = 1 \ x3 = - 1$

Answer 2

спасибо