Question

помогите плс!!! очень надо!!​

Answer 1

$(\frac{m^{2}-2m+4}{4m^{2}-1}*\frac{2m^{2}+m}{m^{3}+8}-\frac{m+2}{2m^{2}-m} ):\frac{5}{m^{2}+2m} -\frac{10m+1}{5-10m} =(\frac{m^{2}-2m+4}{(2m-1)(2m+1)}*\frac{m(2m+1)}{(m+2)(m^{2}-2m+4)}-\\\\-\frac{m+2}{m(2m-1)} ):\frac{5}{m(m+2)} -\frac{10m+1}{5(1-2m)} =(\frac{m}{(2m-1)(m+2)} -\frac{m+2}{m(2m-1)} ):\frac{5}{m(m+2)} -\frac{10m+1}{5(1-2m)}=\\\\=\frac{m^{2}-(m+2)^{2}}{m(2m-1)(m+2)} *\frac{m(m+2)}{5} -\frac{10m+1}{5(1-2m)}=\frac{-4m-4}{m(2m-1)(m+2)} *\frac{m(m+2)}{5} -\frac{10m+1}{5(1-2m)}=$

$=\frac{-4m-4}{5(2m-1)} -\frac{10m+1}{5(1-2m)} =\frac{4m+4}{5(1-2m)} -\frac{10m+1}{5(1-2m)} =\frac{4m+4-10m-1}{5(1-2m)} =\frac{3-6m}{5(1-2m)} =\frac{3(1-2m)}{5(1-2m)} =\\\\=\frac{3}{5}$