Question

Помогите, как это решать?

Answer 1

$\left \{ {{\sqrt[4]{x}+\sqrt[4]{y}=3} \atop {\sqrt{x}-\sqrt{y}=3}} \right. \\\\\sqrt[4]{x}=m>0,\Rightarrow \sqrt{x}=m^{2}\\\\\sqrt[4]{y} =n<0,\Rightarrow \sqrt{y}=n^{2}\\\\\left \{ {{m+n=3} \atop {m^{2}-n^{2}=3}} \right.$

$\left \{ {{m+n=3} \atop {(m+n)(m-n)=3}} \right.\\\\\left \{ {{m+n=3} \atop {3*(m-n)=3}} \right. \\\\+\left \{ {{m+n=3} \atop {m-n=1}} \right.\\------\\2m=4\\m=2\\\\n=3-m=3-2=1\\\\\sqrt[4]{x}=2\\\\x=16\\\\\sqrt[4]{y} =1\\\\y=1\\\\Otvet:\boxed{(16;1)}$