Question

Помогите интеграл и дифиринцирование

Answer 1

1
(2x^4+sinx-1)`=(2x^4)`+(sinx)`-(1)`=2*4*x^3+cosx-0=8x³+cosx
2
[(x²-x)/cosx]`=[(x²-x)`*cosx-(cosx)`*(x²-x)]/cos²x=
=[(2x-1)*cosx+sinx*(x²-x)]/cos²x
3
$intlimits {(2/x^2+1/x+2)} , dx =-2/x+lnx+2x+C$
4
$intlimits^3_0 {(sinx-1)} , dx =-cosx-x|^3_0=-cos3-3+cos0+0=-cos3-3+1$$=-cos3-2$