Question

Помогите эти задания решить

Answer 1

Ответ:

$57\frac{3}{8};$ $\frac{1}{6};$

Пошаговое объяснение:

$3) (\frac{12*12+5}{12}+\frac{1*3+2}{3}-\frac{3*6+5}{6}+\frac{2*4+3}{4}) : (\frac{2*2+1}{2}*\frac{2}{5}-\frac{7}{9}) = (\frac{149}{12}+\frac{5}{3}-\frac{23}{6}+\frac{11}{4}) :$

$: (\frac{5}{2}*\frac{2}{5}-\frac{7}{9}) = \frac{149+5*4-23*2+11*3}{12} : (1-\frac{7}{9}) = \frac{149+20-46+33}{12} : \frac{2}{9} = \frac{149+53-46}{12} * \frac{9}{2} =$

$= \frac{149+7}{12}*\frac{9}{2} = \frac{153}{12}*\frac{9}{2} = \frac{51}{4}*\frac{9}{2} = \frac{51*9}{4*2} = \frac{459}{8} = \frac{456+3}{8} = \frac{456}{8} + \frac{3}{8} = 57\frac{3}{8};$

$4) \frac{48*5+3}{5} : \frac{6*4+3}{4} * \frac{5}{12} - \frac{2*6+5}{6} + \frac{1*94+75}{94} * (\frac{1*2+1}{2} * \frac{1}{3} - \frac{13}{26}) = \frac{243}{5} * \frac{4}{27} * \frac{5}{12} -$

$- \frac{17}{6} + \frac{169}{94} * (\frac{3}{2} * \frac{1}{3} - \frac{1}{2}) = \frac{243*4*5}{5*27*12} - \frac{17}{6} + \frac{169}{94} * (\frac{3*1}{2*3} - \frac{1}{2}) = \frac{243}{27*3} - \frac{17}{6} + \frac{169}{94} *$

$* (\frac{1}{2} - \frac{1}{2}) = \frac{243}{81} - \frac{17}{6} + \frac{169}{94} * 0 = 3 - \frac{17}{6} + 0 = \frac{18}{6} - \frac{17}{6} = \frac{18-17}{6} = \frac{1}{6};$