Question

Помогите Алгебра 9 класс​

Answer 1

$3(x^{2} +4)-frac{6}{x^{2} +4}=17\\x^{2}+4=m,m>0\\3m-frac{6}{m}-17=0\\frac{3m^{2}-17m-6 }{m}=0\\left { {{3m^{2}-17m-6=0 } atop {mneq 0}} right.\\3m^{2}-17m-6=0\\D=(-17)^{2}-4*3*(-6)=289+72=361=19^{2}\\m_{1}=frac{17+19}{6}=6\\m_{2}=frac{17-19}{6}=-frac{1}{3}<0-neyd\\x^{2}+4=6\\x^{2}=2\\x_{1} =-sqrt{2}\\x_{2} =sqrt{2}\\Otvet:boxed{-sqrt{2},sqrt{2}}$

$- sqrt{2} *sqrt{2}=-(sqrt{2})^{2}=-2\\Otvet:boxed{-2}$