Question

помогите
3 вариант
9 класс

Answer 1

task/30385841  "решение "  см ПРИЛОЖЕНИЕ

Answer 2

Здравствуйте,помогите по алгебре!

Answer 3

https://znanija.com/task/30391362

Answer 4

1.
$14 times 8 {}^{ frac{1}{3} } = 14 times (2 {}^{3} ) {}^{ {}^{ frac{1}{3} } } = 14 times 2 = 28$
$32 {}^{ - frac{1}{5} } = (2 {}^{5} ) {}^{ frac{1}{5} } = 2$
2.
$x {}^{ frac{1}{2} } times x {}^{ - frac{1}{6} } = x {}^{ - frac{1}{3} } = frac{1}{x {}^{ frac{1}{3} } } = frac{1}{ sqrt[3]{x} }$
$frac{ a times a {}^{ - frac{3}{8} } }{a {}^{ frac{1}{4} } } = a {}^{ frac{5}{4} } times a {}^{ - frac{1}{4} } = a$
$( {b}^{ frac{1}{8} } ) {}^{8} times b {}^{ - frac{1}{3} } = b times b {}^{ - frac{1}{3} } = b {}^{frac{2}{3} }$
3.
$sqrt[3]{a {}^{5} } times a {}^{ - frac{1}{6} } = a {}^{ frac{5}{3} } times a {}^{ - frac{1}{6} } = a {}^{1.5}$
4.
$frac{a + 3a {}^{ frac{1}{2} } }{a {}^{ frac{1}{2} } + 3} = frac{a {}^{ frac{1}{2} } (a { }^{ frac{1}{2} } + 3)}{a {}^{ frac{1}{2} } + 3 } = a {}^{1.5}$

$frac{x - 36}{ x^{ frac{1}{2} } - 6} = frac{(x { {}^{ frac{1}{2} } } - 6)(x {}^{ frac{1}{2} } + 6)}{ {x}^{ frac{1}{2} } - 6} = {x}^{ frac{1}{2} } + 6$

Answer 5

! 1 б) , 2 a) , 2 б) , 4 а)