Question

Помогите, 100 баллов даю.

Answer 1

1
(1+x-(x²+3)/(x+1))*(1/4-(1/2)²)=0
1)1+x-(x²+3)/(x+1)=(1+2x+x²-x²-3)/(x+1)=(2x-2)/(x+1)
2)1/4-(1/2)²=1/4-1/4=0
3)(2x-2)/(x+1)*0=0
2
a)2x/(x-y)+7x²/x²y²=2x/(x-y)+7/y²=(2xy²+7x-7y)/[y²(x-y)]
b)3a(1-2b)/a^4b³ * 2a²b/[(1-2b)(1+2b)]=6/[ab²(1+2a)]

Answer 2

Я закосячил и минут не написал

Answer 3

минус*