Question

Помогите
1) sin(2π-π/6) =?
2) sin(-2π-π/3) = ?

Answer 1

$1)Sin(2pi-frac{pi }{6})=-Sinfrac{pi }{6}=-frac{1}{2}\\2) Sin(-2pi-frac{pi }{3})=-Sin(2pi+frac{pi }{3})=-Sinfrac{pi }{3}=-frac{sqrt{3}}{2}$