Question

помогииииите,сос!!!1.9 )

Answer 1

$y=8x^2+sqrt[3]{x^4}-frac{4}{x}-frac{2}{x^3} \\y=8x^2+x^{frac{4}{3}}-4x^{-1}-2cdot x^{-3}\\y'=16x+frac{4}{3}cdot x-4cdot (-1)x^{-2}-2(-3)x^{-4}=16x+frac{4}{3}x+frac{4}{x^2}+frac{6}{x^4}$