Question

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(a+2)(a²-2a+4)=
(x+3)(x²-3x+9)=
(m-4)(m²+4m+16)=

(2x-y_(4x²+2xy+y²)=
(3a-2b)(9a²+6ab+4b²)=
(1+c)(1-c+c²)=

Answer 1

(a+2)(a²-2a+4)=а³+8
(x+3)(x²-3x+9)=х³+27
(m-4)(m²+4m+16)=m³-64

(2x-y)(4x²+2xy+y²)=8х³-у³
(3a-2b)(9a²+6ab+4b²)=27а³-8b³
(1+c)(1-c+c²)=1+c³