Question

подскажите пожалуйста​

Answer 1

Ответ:

2,5

Объяснение:

$\frac{x}{x+5} +\frac{x+5}{x-5} =\frac{50}{x^2-25}\\ \\\\\frac{x^2-5x +(x+5)^2}{x^2-25} =\frac{50}{x^2-25}\\\\\\\frac{x^2-5x +x^2+10x+25}{x^2-25} =\frac{50}{x^2-25}\\\\\\\frac{x^2-5x +x^2+10x+25}{x^2-25} =\frac{50}{x^2-25}\\\\\\\frac{2x^2+5x-25}{x^2-25} =0\\\\\\\frac{2x^2+5x-25}{x^2-25} =0\\\\\\D=25+200=225=15^2\\\\x_{12}=\frac{-5+15}{4}=(5)(2,5)$