Question

Пмогите со 2 пожалуйста!!!!

Answer 1

$\frac{3x-1}{x^2}+\frac{x-9}{3x}=\frac{9x-3+x^2-9x}{3x^2}=\frac{x^2-3}{3x^2}\\\\\\\frac{1}{2a-b}-\frac{1}{2a+b}=\frac{2a+b-(2a-b)}{(2a-b)(2a+b)}=\frac{2b}{4a^2-b^2}\\\\\\\frac{5}{c+3}-\frac{5c-2}{c^2+3c}=\frac{5c-(5c-2)}{c(c+3)}=\frac{2}{c^2+3c}$

Answer 2

$1)\frac{3x-1}{x^{2}}+\frac{x-9}{3x}=\frac{9x-3+x^{2}-9x }{3x^{2}}=\frac{x^{2}-3}{3x^{2}}\\\\2)\frac{1}{2a-b} -\frac{1}{2a+b}=\frac{2a+b-2a+b}{(2a-b)(2a+b)}=\frac{2b}{4a^{2}-b^{2}}\\\\3)\frac{5}{c+3}-\frac{5c-2}{c^{2}+3c}=\frac{5}{c+3}-\frac{5c-2}{c(c+3)}=\frac{5c-5c+2}{c(c+3)} =\frac{2}{c^{2} +3c}$