Памагите ришить з 1 по 6.
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Ответил oganesbagoyan
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task/28538878
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1. =10*x⁵/5 +C =2x⁵ +C .
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2. =(6/7)∫(1/x)dx=(6/7)Ln|x| +C. * * * (6/7)*Ln|Cx| * * *
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3. =(1/5) ∫x⁻² dx = (1/5)* x⁻²⁺¹ /(-2+1) +C = -1/(5x) +C .
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4. =(3/8)∫ (1/cos²x)dx = (3/8)*tgx + C.
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5. ∫ (3sinx +2cosx)dx = ∫3sinxdx+ ∫2cosxdx =3∫sinxdx+2∫cosxdx = -3cosx +2sinx +C .
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6. =7∫x ^(-1/2)dx - 6 ∫x²dx + 2∫x^(1/2) dx =
7*x^( -1/2 +1) /( -1/2 +1) -6x³/3+ 2*x^(1+1/2) / (1+1/2) +C =
14√x - 2x³ +4√x³ /3 +C.
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1. =10*x⁵/5 +C =2x⁵ +C .
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2. =(6/7)∫(1/x)dx=(6/7)Ln|x| +C. * * * (6/7)*Ln|Cx| * * *
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3. =(1/5) ∫x⁻² dx = (1/5)* x⁻²⁺¹ /(-2+1) +C = -1/(5x) +C .
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4. =(3/8)∫ (1/cos²x)dx = (3/8)*tgx + C.
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5. ∫ (3sinx +2cosx)dx = ∫3sinxdx+ ∫2cosxdx =3∫sinxdx+2∫cosxdx = -3cosx +2sinx +C .
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6. =7∫x ^(-1/2)dx - 6 ∫x²dx + 2∫x^(1/2) dx =
7*x^( -1/2 +1) /( -1/2 +1) -6x³/3+ 2*x^(1+1/2) / (1+1/2) +C =
14√x - 2x³ +4√x³ /3 +C.
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