Question

p-d$frac{p-d}{p} * ( frac{p}{p-d} + frac{p}{q} )$

Answer 1

$displaystyle frac{p-d}{p}*( frac{p}{p-d}+ frac{p}{q})= frac{p-d}{p}* frac{pq+p(p-d)}{q(p-d)}= frac{q+p-d}{q}= \ \ =1+ frac{p-d}{q} ;$