Question

Ооочень срочно.. Помогите плиз

Answer 1

Ответ:

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Объяснение:

Answer 2

$1)\; \; \log_54=a\; ,\; log_53=b\\\\log_512=log_5(4\cdot 3)=log_54+log_53=a+b\\\\\\2)\; \; \left \{ {{\sqrt{x}-\sqrt{y}=1} \atop {x-y=3}} \right.\; \; \left \{ {{\sqrt{x}-\sqrt{y}=1\qquad \qquad } \atop {(\sqrt{x}-\sqrt{y})(\sqrt{x}+\sqrt{y})=3}} \right.\; \; \left \{ {{\sqrt{x}-\sqrt{y}=1} \atop {\sqrt{x}+\sqrt{y}=3}} \right.\; \; \left \{ {{2\sqrt{x}=4} \atop {2\sqrt{y}=2}} \right.\\\\\left \{ {{\sqrt{x}=2} \atop {\sqrt{y}=1}} \right.\; \; \left \{ {{x=4} \atop {y=1}} \right.\; \; \Rightarrow \; \; (4,1)$

$3)\; \; log_8log_{25}625-\frac{2}{3}\, log_327=log_8(log_{25}25^2)-\frac{2}{3}\, log_33^3=log_{8}2-\frac{2}{3}\cdot 3=\\\\=\frac{1}{3}\, log_22-2=\frac{1}{3}-2=-1\frac{2}{3}$