Question

не знаю как решить, помогите

Answer 1

$f(x)=(x-6)(x+1)(x+2),\ f(x)=0, (x-6)(x+1)(x+2)=0, \ left[begin{array}{c}x-6=0,\x+1=0,\x+2=0;end{array}right. left[begin{array}{c}x=6,\x=-1,\x=-2;end{array}right. \ x textless -2, f(x) textless 0,\ -2 textless x textless -1, f(x) textgreater 0, \ -1 textless x textless 6, f(x) textless 0, \ x textgreater 6, f(x) textgreater 0; \ x_{max}in(-2;-1), x_{min}in(-1;6); \ xin(-infty;x_{max}), xin(x_{min};+infty) ynearrow, \ xin(x_{max};x_{min}) ysearrow; \ a=2, b=1, c=1, d=1; \ a+2b+3c+4d=2+2+3+4=11.$