Question

Найти производную функции.

Answer 1

$f(x)=(5x^2+7)^6 \ f'(x)=6(5x^2+7)^5*10x=60x(5x^2+7)^5$

$y=sqrt{x^2+3} \ y'=frac{2x}{2sqrt{x^2+3}}=frac{x}{sqrt{x^2+3}}$

$f(x)=5cosx+3tgx-7sqrt{3} \ f'(x)=-5sinx+frac{3}{cos^2x}$

Answer 2

a
f`(x)=6*(5x²+7)^5 *10x=60x(5x²+7)^5
b
y`=1/2√(x²+3)  *2x=x/√(x²+3)
c
f`(x)=-5sinx+3/cos²x