Question

найти производную (3-2 tgx) , в точке х 0 = -Пи

Answer 1

y=3-2tgx

y'=-2/(cosx)^2

y'(-pi)=-2/(cos(-pi))^2=-2/1^2=-2

Answer 2

(3-2tgx)¹=-2/cos²x

x₀=-π, y¹(-π)= -2/cos²(-π)= -2/cos²π=-2/(-1)²= -2