Question

найти первообразную f(x)=2/cos^2(3x+1)-3 sin(4-x)+2x

Answer 1

$f(x) = frac{2}{cos^2(3x+1)}-3sin(4-x)+2x$

$F(x) = int{(frac{2}{cos^2(3x+1)}-3sin(4-x)+2x)}, dx=$ $2int{frac{1}{cos^2(3x+1)}, dx-3int{sin(4-x)}, dx+2int{x}, dx=$$frac{2}{3}int{frac{1}{cos^2(3x+1)}, d(3x+1)+3int{sin(4-x)}, d(4-x)+2int{x}, dx=$$frac{2}{3}tg(3x+1)-3cos(4-x)+x^2$